If `tanx=b/a ,` then `sqrt((a+b)/(a-b))+sqrt((a-b)/(a+b))` is equal to (a)`2sinx//sqrt(sin2x)` (b) `2cosx//sqrt(cos2x)` (c)`2cosx//sqrt(sin2x)` (d) `2sinx//sqrt(cos2x)`

Explanation

To solve the problem, we start with the expression given in the question:

\[ \sqrt{\frac{a+b}{a-b}} + \sqrt{\frac{a-b}{a+b}} \]

Given that \( \tan x = \frac{b}{a} \), we need to simplify the expression step by step.

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