" ii) "(1+tan^(2)theta)cos theta*sin theta=tan theta

Solve sin^(2)theta tan theta+cos^(2)theta cot theta-sin2 theta=1+tan theta+cot theta

Solve sin^2 theta tan theta+cos^2 theta cot theta-sin 2 theta=1+tan theta+cot theta

(1-sin theta)/(cos theta)-(cos theta)/(1+sin theta)=2tan theta

Prove that (cos theta)/((1-tan theta))-(sin^(2)theta)/((cos theta-sin theta))=(cos theta+sin theta)

If tan theta=4 then ((tan theta)/((sin^(3)theta)/(cos theta)+sin theta cos theta)) is equal to

Consider f(theta)=|[tan theta,cos theta,sin theta],[cos theta,sin theta,tan theta],[sin theta,tan theta,cos theta]| then f((pi)/(4))+f(0) = ?

Prove that (1- cos theta + sin theta)/( 1+cos theta +sin theta) = "tan"(theta)/(2) .

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta