(1)/(8)(1)/(x+x log x)

log x-(1)/(2)log(x-(1)/(2))=log(x+(1)/(2))-(1)/(2)log(x+(1)/(8))

int(log(x+1)-log x)/(x(x+1))dx= (A) log(x-1)log x+(1)/(2)(log x-1)^(2)-(1)/(2)(log x)^(2)+c (B) (1)/(2)(log(x+1))^(2)+(1)/(2)(log x)^(2)-log(x+1)log x+c (C) -(1)/(2)(log(x+1)^(2))-(1)/(2)(log x)^(2)+log x*log(x+1)+c (D) [log(1+(1)/(x))]^(2)+c

The value of int(1)/(x+x log x)dx is 1+log x(b)x+log x(c)x log(1+log x)(d)log(1+log x)

log_(10)x-(1)/(2)log_(10)(x-(1)/(2))=log_(10)(x+(1)/(2))-(1)/(2)log_(10)(x+(1)/(8))

intx^(3) log x dx is equal to A) (x^(4) log x )/( 4) + C B) (x^(4))/( 8) ( log x - ( 4)/( x^(2)))+C C) (x^(4))/( 16) ( 4 log x -1) +C D) (x^(4))/( 16) ( 4 log x +1) + C

Integrate the functions ,(1+x)(x+log x)^(2),((1+x)(x+log x)^(2))/(x)

int (1+log x)/(1+x log x)dx=

If log_((1)/(8))(log_((1)/(4))(log_((1)/(2))x))=(1)/(3)th n x is

Find the integral int(1)/(4x^(2)+12x+5)dx A. (1)/(4)log|(2x+1)/(2x-5)|+C B. (1)/(8)log|(1+2x)/(5-2x)|+C C. (1)/(8)log|(2x-1)/(2x+5)|+C D. (1)/(4)log|(1-2x)/(5+2x)|+C