[" 16"],[[" a."5," If "A_(1)=|[1,1,1],[a,b,c],[a^(2),b^(2),c^(2)]|]|Delta z=|[1,bc,a],[1,ca,b],[1,ab,c]|" then "],[qquad [,=2Delta_(2)=0]" (c) "Delta_(1)=Delta_(2)]

If A=|[1, 1, 1],[a, b, c],[ a^2,b^2,c^2]| , B=|[1,bc, a],[1,ca, b],[1,ab, c]| , then

If Delta_(1) = |(1,1,1),(a,b,c),(a^(2),b^(2),c^(2))|, Delta_(2) = |(1,bc,a),(1,ca,b),(1,ab,c) | , then

If Delta_1=|(1,1,1),(a,b,c),(a^2,b^2,c^2)|, Delta_2=|(1,bc,a),(1,ca,b),(1,ab,c)| , then

If Delta_1=|{:(1,1,1),(a,b,c),(a^2,b^2,c^2):}| and Delta_2=|{:(1,bc,a),(1,ac,b),(1,ab,c):}| then : -

Delta=det[[1,a,bc1,b,ca1,c,ab]]

If Delta_1=|(1, 1 ,1),(a, b, c ),(a^2,b^2,c^2)|,Delta_2=|(1,b c, a),(1,c a, b),(1,a b, c)|,t h e n (a) Delta_1+Delta_2=0 (b) Delta_1+2Delta_2=0 (c) Delta_1=Delta_2 (d) none of these

Prove that |[1,1,1] , [a,b,c] ,[a^2-bc, b^2-ca, c^2-ab]|=0

If Delta_(1)=|(1,a,bc),(1,b,ca),(1,c,ab)|,Delta_(2)=|(1,a,a^(2)),(1,b,b^(2)),(1,c,c^(2))| then

Evaluate : triangle = |[1,a,bc],[1,b,ca],[1,c,ab]|