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The value of cos(1/2cos^(-1)(1/8)) is...

The value of `cos(1/2cos^(-1)(1/8))` is

A

`3/4`

B

`-3/4`

C

`1/16`

D

`1/4`

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( \cos\left(\frac{1}{2} \cos^{-1}\left(\frac{1}{8}\right)\right) \), we can follow these steps: ### Step 1: Set up the equation Let \( \theta = \cos^{-1}\left(\frac{1}{8}\right) \). This means that \( \cos(\theta) = \frac{1}{8} \). ### Step 2: Use the half-angle formula We need to find \( \cos\left(\frac{\theta}{2}\right) \). The half-angle formula for cosine is given by: \[ \cos\left(\frac{\theta}{2}\right) = \sqrt{\frac{1 + \cos(\theta)}{2}} \] ### Step 3: Substitute the value of \( \cos(\theta) \) Substituting \( \cos(\theta) = \frac{1}{8} \) into the half-angle formula: \[ \cos\left(\frac{\theta}{2}\right) = \sqrt{\frac{1 + \frac{1}{8}}{2}} \] ### Step 4: Simplify the expression First, simplify the numerator: \[ 1 + \frac{1}{8} = \frac{8}{8} + \frac{1}{8} = \frac{9}{8} \] Now substitute this back into the half-angle formula: \[ \cos\left(\frac{\theta}{2}\right) = \sqrt{\frac{\frac{9}{8}}{2}} = \sqrt{\frac{9}{16}} = \frac{3}{4} \] ### Step 5: Conclusion Thus, the value of \( \cos\left(\frac{1}{2} \cos^{-1}\left(\frac{1}{8}\right)\right) \) is: \[ \frac{3}{4} \]

To find the value of \( \cos\left(\frac{1}{2} \cos^{-1}\left(\frac{1}{8}\right)\right) \), we can follow these steps: ### Step 1: Set up the equation Let \( \theta = \cos^{-1}\left(\frac{1}{8}\right) \). This means that \( \cos(\theta) = \frac{1}{8} \). ### Step 2: Use the half-angle formula We need to find \( \cos\left(\frac{\theta}{2}\right) \). The half-angle formula for cosine is given by: \[ ...
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