" (1) "2tan^(-1)(sin x)=tan^(-1)(2sec x),x!=(pi)/(2)

Solve for x:2tan^(-1)(sin x)=tan^(-1)(2sec x),x!=(pi)/(2)

Solve the following equations: 2 tan^-1(sinx) = tan^-1(2 sec x), x = pi/2

Solve the following equations : 2tan^(-1) (sin x) = tan^(-1) (2sec x ,) 0 lt x lt pi/2

Solve the following equations: 2 tan^-1(sinx) = tan^-1(2 sec x), x ne pi/2

sin^(-1)x+tan^(-1)x=(pi)/(2)

The value of the definite integral (1)/(pi)int_((pi)/(2))^((5 pi)/(2))(e^(tan^(-1)(sin x)))/(e^(tan^(-1)(sin x)+e^(tan^(-1)(cos x)))dx is )

If sin^(-1)x+tan^(-1)((1)/(2))=(pi)/(2) then x=

Differentiate the following functions with respect to x:tan^(-1)(sec x+tan x),-(pi)/(2)

Prove that int_(0)^(pi//2) tan^(-1)(sin x) .sin 2x = (pi)/(2)-1

Range of f(x)=(sec x+tan x-1)/(tan x-sec x+1)x in(0,(pi)/(2))