If `sin^(-1)a+sin^(-1)b+sin^(-1)c=pi,` then the value of `asqrt((1-a^2))+bsqrt((1-b^2))+sqrt((1-c^2))` will be (A) `2a b c` (B) `a b c` (C) `1/2a b c` (D) `1/3a b c`

Explanation

To solve the problem, we start with the given equation:

\[ \sin^{-1} a + \sin^{-1} b + \sin^{-1} c = \pi \]

### Step 1: Understand the implications of the equation
From the equation, we can infer that \( a, b, c \) are angles in a triangle because the sum of the angles in a triangle is \( \pi \). Therefore, we can express \( c \) in terms of \( a \) and \( b \):
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