If `cos(2sin^(-1)x)=1/9,` then find the values of `xdot`

Explanation

To solve the equation \( \cos(2\sin^{-1}x) = \frac{1}{9} \), we will follow these steps:

### Step 1: Set up the equation
Let \( \alpha = \sin^{-1}x \). Then, we can rewrite the equation as:
\[ \cos(2\alpha) = \frac{1}{9} \]

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