If ` sin2A= lambda sin 2B` prove that `(tan(A+B)/tan(A-B))=(lambda+1)/(lambda-1)`

If sin2A=lambda sin2B prove that ((tan(A+B))/(tan(A-B)))=(lambda+1)/(lambda-1)

sin B=3sin(2A+B), prove that2tan A+tan(A+B)=0

If s in2A=lambda sin2B, then write the value of (lambda+1)/(lambda-1)

If2tan A=3tan B, then prove that sin(A+B)=5sin(A-B)

If cos A+cos B=(1)/(2) and sin A+sin B=(1)/(4) prove that: tan((A+B)/(2))=(1)/(2)

Prove that: If tan A=x tan B, prove that (sin(A-B))/(sin(A+B))=(x-1)/(x+1)

If tan(A+B)=3 tan A , prove that (a) sin(2A+B)=2sin B

Prove that :(tan A+tan B)/(tan A-tan B)=(sin(A+B))/(sin(A-B))

If sec theta+tan theta=lambda then prove that (lambda^2-1)/(lambda^2+1)=sin theta

A straight line L cuts the lines A B ,A Ca n dA D of a parallelogram A B C D at points B_1, C_1a n dD_1, respectively. If ( vec A B)_1,lambda_1 vec A B ,( vec A D)_1=lambda_2 vec A Da n d( vec A C)_1=lambda_3 vec A C , then prove that 1/(lambda_3)=1/(lambda_1)+1/(lambda_2) .