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For a positive integer n , let fn(theta)...

For a positive integer `n ,` let `f_n(theta)=(tantheta//2)(1+sectheta)(1+sec2theta)(1+sec4theta)(1+sec2^ntheta)dotT h e n` `f_2(pi/(16))=1` (b) `f_3(pi/(32))=1` `f_4(pi/(64))=1` (d) `f_5(pi/(128))=1`

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For a positive integer n , let f_n(theta)=(tantheta//2)(1+sectheta)(1+sec2theta)(1+sec4theta)...................(1+sec2^ntheta). Then (a)f_2(pi/(16))=1 (b) f_3(pi/(32))=1 (c)f_4(pi/(64))=1 (d) f_5(pi/(128))=1

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