[x+y=5xy],[3x+2y=13xy]

Solve the following system of equations: x+y=5xy,quad 3x+2y=13xy,quad x!=0,quad y!=0

x + y = 5 xy , 3x + 2y = 13 xy ( x ne 0, y ne 0 )

Solve for x and y : 2(3x-y)=5xy, 2(x+3y)=5xy ,

if y + x = 5xy , y - x = -xy

Solve for x and y, by reducing the following equations in a pair of linear equations : 2x + 3y = 5xy and 3x - 2y = xy.

6x+3y=6xy; 2x+4y=5xy

If 4x - 3y = 7xy and 3x + 2y = 18xy , then (x,y) =

Solve : {:(x+y=7xy),(2x-3y=-xy):}

Add the following 5y^2x^2, -6xy, 8x^2y^2, 3xy