" al "int_(0)^( pi)log(1+cos x)dx" is "

By using the properties of definite integrals, evaluate the integrals int_(0)^( pi)log(1+cos x)dx

By using the properties of definite integrals, evaluate the integrals int_(0)^(pi)log(1+cos x) dx

int_(0)^( pi)(dx)/(1+cos x)

Prove that, int_(0)^(pi)log(1+cos x)dx=-pi log2 , given int_(0)^((pi)/(2))log((sin x))dx=(pi)/(2)"log"(1)/(2) .

int_(0)^((pi)/(2))log(cos x)dx=

Find I=int_(0)^( pi)ln(1+cos x)dx

int_(0)^( pi)cos2x*log(sin x)dx

int_(0)^(pi) x log sinx\ dx

int_(0)^(pi) x log sinx\ dx