The normal chord of `y^(2)=4ax` at a point where abscissa is equal to ordinate subtends at the focus an angle `theta`

The normal meet the parabola y^(2)=4ax at that point where the abscissa of the point is equal to the ordinate of the point is

If "P" is a point on the parabola " y^(2)=4ax " in which the abscissa is equal to ordinate then the equation of the normal at "P" is

Prove that the normal chord to a parabola at the point whose ordinate is equal to the abscissa subtends a right angle at the focus.

The point on y^(2)=4ax nearest to the focus has to abscissa equal to

Number chords of y^(2)=4ax Whose Mid Point is the focus is

Normal at point to the parabola y^(2)=8x where abscissa is equal to ordinate,will meet the parabola again at a point

The normal chord of a parabola y^(2)=4ax at the point P(x_(1),x_(1)) subtends a right angle at the

Consider a parabola y^(2)=4x with vertex at A and focus at S. PQ is a chord of the parabola which is normal at point P. If the abscissa and the ordinate of the point P are equal, then the square of the length of the diameter of the circumcircle of triangle PSQ is