If `alpha,beta(alpha < beta)` are the roots of equation `6x^2+11="" x+3="0` , then which following real? (a) `cos^(-1)alpha` (b) `sin^(-1)beta` (c) `cosec^(-1)alpha` (d) both `cot^(-1)alpha` and `cot^(-1)beta`

Explanation

`6x^2+11x+3 = 0`

`=>6x^2+9x+2x+3 = 0`

`=>3x(2x+3)+1(2x+3) = 0`

`=>(2x+3)(3x+1) = 0`

`=> x = -3/2 or x = -1/3`

As `alpha` and `beta` ar the roots of the given equation,

`:. alpha = -3/2 or beta = -1/3`

Now, we will check the options.

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