Given both `thetaa n dphi` are acute angles and `sintheta=1/2,cosvarphi=1/3,` then the value of `theta+varphi` belongs to (a)`(pi/3,pi/2]` (b) `(pi/2,(2pi)/3]` (c) `((2pi)/3,(5pi)/6]` (d) `((5pi)/6,pi]`

Given both theta and phi are acute angles and sin theta=(1)/(2),cos varphi=(1)/(3), then the value of theta+varphi belongs to (a)((pi)/(3),(pi)/(2)]( b) ((pi)/(2),(2 pi)/(3)] (c) ((2 pi)/(3),(5 pi)/(6)] (d) ((5 pi)/(6),pi]

If tantheta=1/2a n dt a nvarphi=1/3, then the value of theta+varphi is pi/6 (b) pi (c) 0 (d) pi/4

If tan theta=(1)/(2) andtan varphi =(1)/(3), then the value of theta+varphi is (pi)/(6) (b) pi(c)0(d)(pi)/(4)

For 0 cos^(-1)(sintheta) is true when theta belongs to (a) (pi/4,pi) (b) (pi,(3pi)/2) (c) (pi/4,(3pi)/4) (d) ((3pi)/4,2pi)

If sintheta=1/2a n dcostheta=-(sqrt(3))/2, then the general value of theta is (n in Z)dot (a) 2npi+(5pi)/6 (b) 2npi+pi/6 (c)2npi+(7pi)/6 (d) 2npi+pi/4

If roots of the equation 2x^2-4x+2sintheta-1=0 are of opposite sign, then theta belongs to (pi/6,(5pi)/6) (b) (0,pi/6)uu((5pi)/6,pi) ((13pi)/6,(17pi)/6) (d) (0,pi)

If roots of the equation 2x^2-4x+2sintheta-1=0 are of opposite sign, then theta belongs to (pi/6,(5pi)/6) (b) (0,pi/6)uu((5pi)/6,pi) ((13pi)/6,(17pi)/6) (d) (0,pi)

If roots of the equation 2x^2-4x+2sintheta-1=0 are of opposite sign, then theta belongs to (pi/6,(5pi)/6) (b) (0,pi/6)uu((5pi)/6,pi) ((13pi)/6,(17pi)/6) (d) (0,pi)

sin^(-1)((-1)/2) (a) pi/3 (b) -pi/3 (c) pi/6 (d) -pi/6

If sintheta=1/2a n dcostheta=-(sqrt(3))/2, then the general value of theta is (n in Z)dot (a) 2npi+(5pi)/6 (b) 2npi+pi/6 2npi+(7pi)/6 (d) 2npi+pi/4