Find the general solution of the differential equations:`(dx)/(dy)+secx y=tanx(0lt=x

Explanation

`=>dy/(dx)+ysecx=tanx `

Here, P=secx and Q=tanx

`I.F.=e^(∫Pdx)=e^(∫secx)`

`=>e^(log(secx+tanx))`

`=>secx+tanx`

So, the solution is:

`=>y(secx+tanx)=∫tanx(secx+tanx)dx+c`

`=>∫(secx+tanx+sec2x−1)dx+c`

...