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Find the general solution of the differ...

Find the general solution of the differential equations:`(dx)/(dy)+secx y=tanx(0lt=x

Text Solution

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`=>dy/(dx)+ysecx=tanx `
Here, P=secx and Q=tanx
`I.F.=e^(∫Pdx)=e^(∫secx)`
`=>e^(log(secx+tanx))`
`=>secx+tanx`
So, the solution is:
`=>y(secx+tanx)=∫tanx(secx+tanx)dx+c`
`=>∫(secx+tanx+sec2x−1)dx+c`
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Knowledge Check

  • The general solution of the differential equation x(dy)/(dx)+x =0 is ?

    A
    xy=c
    B
    x=cy
    C
    x+y=c
    D
    `x^(2) +y^(2) =c`

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