Solve `sin^(-1)x+sin^(-1)2x=pi/3dot`

Explanation

To solve the equation \( \sin^{-1} x + \sin^{-1} 2x = \frac{\pi}{3} \), we will follow these steps:

### Step 1: Rewrite the equation
We start with the equation:
\[ \sin^{-1} x + \sin^{-1} 2x = \frac{\pi}{3} \]
From this, we can express \( \sin^{-1} 2x \) in terms of \( \sin^{-1} x \):
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