[" A particle starts from "],[" rest at "t=0" and moves "],[" along a straight line with "],[" a variable acceleration "],[" given by a "(t)=(3t+1)ms^(-2)],[" where "t" is in seconds."],[" The velocity of the "],[" particle at "t=4s" is "]

A particle starts from rest at t=0 and moves in a straight line with an acceleration as shown below. The velocity of the particle at t=3 s is

A car moves along a straight line whose equation of motion is given by s=12t+3t^(2)-2t^(3) where s is in metres and t is in seconds. The velocity of the car at start will be :-

A particle starts from rest, moving in a straight line with a time varying acceleration ( "in"m//s^(2) ): a= 30 -(15)/(2) sqrt(t) , where time is in seconds . The displacement of the particle in 4 seconds is .

The position of the particle moving along x-axis is given by x=2t-3t^(2)+t^(3) where x is in mt and t is in second.The velocity of the particle at t=2sec is

[" A particle is moving along "],[" a straight line with non- "],[" uniform acceleration.The "],[" displacement of the "],[" particle is given by "],[S=2t^(3)+3t^(2)+5t" where "S" is in "],[" metres and "t" is in seconds."],[" The velocity of the particle "],[" at "t=2" seconds is "]

[" A particle is moving along "],[" a straight line with non- "],[" uniform acceleration.The "],[" displacement of the "],[" particle is given by "],[S=2t^(3)+3t^(2)+5t" where "S" is in "],[" metres and "t" is in seconds."],[" The velocity of the particle "],[" at "t=2" seconds is "]

[" If position of particle moving in straight line is "],[" given by "x=(t^(3)-2t+10)m" ,where t is time in "],[" second,then acceleration of particle at "t=1],[" sec is "......]

A particle starts from the origin with a velocity of 10 and moves along a straight line.If its acceleration be (2t^(2)-3t)(cm)/(s^(2)) at the end of t seconds,then find its velocity and the distance from the origin at the end of 6seconds