If COMMON ratio of a geometric progression is positive then maximum value of the ratio of second term to the sum of first 3 terms equals-

In a geometric progression with first term a and common ratio r, what is the arithmetic mean of first five terms?

Soppose that all the terms of an arithmetic progression (AP) are natural numbers. If the ratio of the sum of the first seven terms to the sum of the first eleven terms is 6:11 and the seventh term lies between 130 and 140, then the common difference of this AP is

The sum of the first 2012 terms of a geometric progression is 200. The sum of the first 4024 terms of the same series is 380. Find the sum of the first 6036 terms of the series.

The sum of an infinite geometric progression is 6, If the sum of the first two terms is 9//2 , then what is the first term?

If the sum of the first 23 terms of an arithmetic progression equals that of the first 37 terms , then the sum of the first 60 terms equals .

In a geometric progression consisting of positive terms,each term equals the sum of the next terms.Then find the common ratio.

In a geometric progression with common ratio 'q'the sum of the first 109 terms exceeds the sum of the first 100 terms by 12. If the sum of the first nine terms of the progression is (lambda)/(q^(100)) then the value of lambda equals

The first term of a geometric progression is equal to b-2, the third term is b+6, and the arithmetic mean of the first and third term to the second term is in the ratio 5:3. Find the positive integral value of b .

The sum of the first n-terms of the arithmetic progression is equal to half the sum of the next n terms of the same progression.Find the ratio of the sum of the first 3n terms of the progressionto the sum of its first n-terms.