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If A+B+C=pi, show that : tan.(A)/(2)tan....

If `A+B+C=pi,` show that : `tan.(A)/(2)tan.(B)/(2)+tan.(B)/(2)tan.(C)/(2)+tan.(C)/(2)tan.(A)/(2)=1` Hence deduce that : `cot.(A)/(2)+cot.(B)/(2)+.cot.(C)/(2)=cot.(A)/(2).cot.(B)/(2)tan.(C)/(2)`.

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