Force between two point charges in air at certain distance is `200N`. What will force when they are kept in a medium of dielectric constant `4`, at the same distance?

The force of attraction between two charges separated by certain distance in air is F_(1) .If the space between the charges is completely filled with dielectric of constant 4 the force becomes F_(2) .If half of the distance between the charges is filled with same dielectric the force between the charges is F_(3) Then F_(1):F_(2):F_(3) is

Force of attraction between two point charges placed at a distance 'd' is F. What distance apart should they be kept in the same medium, so that the force between them is 2F ?

Two charges exert a force of 10 N on each other when separated by a distance 0.2 m in air. When they are placed in another medium of dielectric constant K = 4 , and separated by distance R. they exert same force. The distance R equats to

The ratio of the forces between two charges placed at a certain distance apart in air and at half of the distance a part in medium of dielectric 'k' is А) k B) k/3 C) k/2 D) K/4

Two point charges 4e and e each, at a separation r in air, exert force of magnitude F. They are immersed in a medium of dielectric constant 16. What should be the separation between the charges so that the force between them remains unchanged.

Two point charges placed at a distance r in air experience a certain force. Then the distance at which they will experience the same force in a medium of dielectric constant K is

The gravitational force between two masses kept at a certain distance is p N. The same two masses are now kept in water and the distance between them is same. If the gravitational force between these two masses in water is q N, then