2 moles of `H_(2)O_(2)` is treated with equivalent amount of `KMnO_(4)` in the presence of `H_(2)SO_(4)` then moles of `O_(2)` gas liberated is "

2moles of H_(2)O_(2) is treated with equivalent amount of KMnO_(4) in the presence of H_(2)SO_(4) then moles of O_(2) gas liberated is

0.2 g of a sample of H_(2)O_(2) required 10 mL of 1 N KMnO_(4) in a titration in the presence of H_(2)SO_(4) Purity of H_(2)O_(2) is :

If one mole of H_(2)SO_(4) reacts with one mole of NaOH, equivalent weight of H_(2)SO_(4) will be :

In a titration certain amount of H_(2)O_(2) is treated with y mole of KMnO_(4) in acidic medium. The left out KMnO_(4) when treated with X^(+) in basic medium oxidizes X^(+1) " to " X^(+6) and 0.2 M, x L of X^(+) was consumed. The mole of given H_(2)O_(2) solution is :

A solution of 0.4 g sample of H_(2)O_(2) reacted with 0.632 g of KMnO_(4) in presence of sulphuric acid. The percentage purity of the sample of H_(2)O_(2) is :

In a titration of H_(2)O_(2) certain amount is treated with 'y' mole of KMnO_(4) in acidic medium. The mole of H_(2)O_(2) in solution will be :