If `asin x=b cos x=(2c tan x)/(1-tan^(2)x)` then `((a^(2)-b^(2))^(2))/(a^(2)+b^(2))=`
(A) `c^(2)`
(B) `2c^(2)`
(C)`3c^(2)`
(D) `4c^(2)`

If a sin x = b cos x =(2c tan x )/(1- tan^(2) x) " then " ((a^(2)-b^(2))^(2))/(a^2+b^(2))=

In tringle ABC (a^(2)-b^(2)-c^(2))tan A+(a^(2)-b^(2)+c^(2))tan B=

In triangle ABC(a^(2)-b^(2)-c^(2))tan A+(a^(2)-b^(2)+c^(2))tan B=

If a!=b then the length of common chord of the circles (x-a)^(2)+(y-b)^(2)=c^(2) and (x-b)^(2)+(y-a)^(2)=c^(2) is (A)sqrt(4c^(2)-2(a-b)^(2))(B)sqrt(c^(2)-(a-b)^(2))(C)sqrt(3c^(2)-(a-b)^(2))(D)sqrt(2c^(2)(a-b)^(2))(C)

In a triangle tan A:tan B:tan C=1:2:3, then a^(2):b^(2):c^(2) equals

In a ABC, prove the following: (c^(2)-a^(2)+b^(2))tan A=(a^(2)-b^(2)+c^(2))tan B=(b^(2)-c^(2)+a^(2))tan C

((x^(a))/(x^(-b)))^(a^(2)-ab+b^(2))times((x^(b))/(x^(-c)))^(b^(2)-bc+c^(2))times((x^(c))/(x^(-a)))^(c^(2)-ca+a^(2))