`999 9^2`

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In a /_\ABC, b^2+c^2 =1999 a^2 , then (cotB+cotC)/(cotA)= (A) 1/1999 (B) 1/999 (C) 999 (D) 1999

Using suitable identity, evaluate the following 999^2

((999)^(3)-1)/((999)^(2)-1)=?

Evaluate {(999)^2-1} .

(2.0001)^(3)xx(1.999)^(-2)div(3.999)^(-4)=?