The mean of `50` observations is `36`. If its two observations `30` and `42` are deleted, then the mean of the remaining observations is

The mean of 50 observations is 36. If two observations 30 and 42 are deleted, then mean of the remaining observations is

The mean of 50 observation is 36. if two observation 30 and 42 are to be excluded, then the mena of the reamining observations will be-

The arithmetic mean of 12 observations is 15. If two observations 20 and 25 are removed then the arithmetic mean of remaining observations is

The arithmetic of 12 observations is 15. If two observations 20 and 25 are removed then the arithmetic mean of remaining observations is

The arithmetic mean of 10 observations is 45. If one of the obsservations, 54, is deleted, then find the mean of the remaining observations.

The mean of 12 observations is 75. If two observations are discarded, then the mean of the remaining observations is 65. What is the mean of the discarded observations?

The mean of 30 observations is 25. If two observations 30 and 60 are misread as 20 and 40, then find the correct mean.

The A.M. of n observations is M. If the sum of n - 4 observations is a, then the mean of remaining 4 observations is :