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A particle is projected at an angle thet...

A particle is projected at an angle `theta` from the horizontal with kinetic energy (T). What is the kinetic energy of the particle at the highest point ?

Text Solution

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`K=1/2m u^(2),` Kinetic energy at the highest point
`K_(H) =1/2m (u cos theta)^(2)`
`K_(H)=1/2 m u^(2) cos^(2) theta [K_(H)=K cos^(2) theta)]`
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