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A bullet fired at an angle of 30^(@) wit...

A bullet fired at an angle of `30^(@)` with the horizontal hits the ground 3 km away. By adjusting the angle of projection, can one hope to hit a target 5 km away ? Assume the muzzle speed to be fixed and neglect air resistance.

Text Solution

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Horizontal range, `R=(u^(2) sin 2 theta)/(g) rArr (u^(2) sin 60^(@))/(g) rArr (u^(2))/(g)=2sqrt3`
Since the muzzle velocity is fixed. Therefore, maximum horizontal range `R_(max)=(u^(2))/(g)=2sqrt3=3.46 m,` So, the bullet cannot hit the target.
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