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A projectile is fired with kinetic energ...

A projectile is fired with kinetic energy ` 1 kJ.` If the range is maximum , what is its ` K.E.` at the highest point ?

Text Solution

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Here, `1/2mv^(2)=1kJ=1000J`.
For maximum range, `theta=45^(@)` and velocity of projectile at the highest point `=v cos 45^(@)`
At the highest point, `KE=1/2m (v cos 45^(@))^(2) , =1/2 m v^(2)/2=1000/2=500J`
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