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A stone is thrown horizontally with a ve...

A stone is thrown horizontally with a velocity `2sqrtgh` from the top of a tower of height h. It strikes the ground level through the foot of tower at a distance x from it. What is the value of x?

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To solve the problem, we need to find the horizontal distance \( x \) that the stone travels after being thrown horizontally from the top of a tower of height \( h \). The stone is thrown with a velocity of \( v = 2\sqrt{gh} \). ### Step 1: Determine the time of flight \( t \) The time it takes for the stone to fall to the ground can be calculated using the vertical motion equations. Since the stone is dropped from a height \( h \) with an initial vertical velocity of \( 0 \) and an acceleration due to gravity \( g \), we can use the equation of motion: \[ s = ut + \frac{1}{2} a t^2 \] ...
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