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Average velocity of a particle in projec...

Average velocity of a particle in projectile motion between its starting point and the highest point of its trajectory is (projectin speed = u, angle projection from horizontal =`theta`)

A

`u cos theta`

B

`u/2 sqrt(1+ cos^2 theta)`

C

`u/2 sqrt(2+ cos^2 theta)`

D

`u/2 sqrt(1+cos^2 t heta)`

Text Solution

Verified by Experts

The correct Answer is:
B
`v_(av)=(AB)/(t//2)" where "AB=sqrt(h^(2)+R^(2)//4)`
`h=(u^(2) sin^(2) theta)/(2g), R=(u^(2))/(g) sin 2 theta`
`t=(2u sin theta)/(g)`
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