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The horizontal and vertical displacement...

The horizontal and vertical displacements x and y of a projectile at a given time t are given by `x= 6 "t" and y= 8t -5t^2` meter.The range of the projectile in metre is:

A

9.6

B

10.6

C

19.2

D

38.4

Text Solution

Verified by Experts

The correct Answer is:
A
`x=(u cos theta)t=6t, y=(u sin theta)t-1/2 gt^(2)=8t-5t^(2)`
Therefore `u sin theta=8`
`u cos theta=-6`
Range, `R=(u^(2) sin 2 theta)/(g), =(u^(2) xx 2 sin theta cos theta)/(g)`
`=(2(u sin theta)(u cos theta))/(g), =(2(8)(6))/(10)=9.6m`
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