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The equation of a projectile is y=sqrt(3...

The equation of a projectile is `y=sqrt(3)x-(gx^(2))/(2)`
the angle of projection is:-

A

`pi/6`

B

`pi/3`

C

`pi/2`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B
`y=sqrt3x -(gx^(2))/(2), tan theta=sqrt3 rArr theta=60^(@)`
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