Home
Class 12
PHYSICS
A cannon on a level plane is aimed at an...

A cannon on a level plane is aimed at an angle `theta` above the horizontal and a shell is fired with a muzzle velocity `v_(0)` towards a vertical cliff a distance D away. Then the height from the bottom at which the shell strikes the side walls of the cliff is

A

` R sin alpha -1/2 (gR^2)/(v_0^2 sin^2alpha)`

B

`R cos alpha- 1/2 (gR^2)/(v_0^2cos ^2 alpha)`

C

`R tan alpha -1/2 (gR^2)/(v_0^2 sin ^2 alpha)`

D

`R tan alpha -1/2 (gR^2)/(v_0^2 sin ^2 alpha)`

Text Solution

Verified by Experts

The correct Answer is:
C


P should satisfy equation of trajectory
`h=R tan alpha -(gR^(2))/(2v_(0)^(2) cos^(2) alpha)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A cannon of mass 5m (including a shell of mass m) is at rest on a smooth horizontal ground, fires the shell with its barrel at an angle theta with the horizontal at a velocity u relative to cannon. Find the horizontal distance of the point where shell strikes the ground from the initial position of the cannon :-

A small ball thrown at an initial velocity v_(0) at an angle alpha to the horizontal strikes elastically with a smooth vertical wall moving towards it at a horizontal velocity v and returns to the point from which it was thrown. Determine the time t from the beginning of motions to the moment of impact with vertical wall. Neglect friction losses.

A projectile, thrown with velocity v_(0) at an angle alpha to the horizontal, has a range R. it will strike a vertical wall at a distance R//2 from the point of projection with a speed of

A target situated on a hill can be seen from the foot at angle alpha above the horizontal .The distance of the target along the horizonal is R. if a shell is fired from the foot at an angle beta with the horizontal, find the velocity required for it to strike the target.

A shell is fired from a gun from the bottom of a hill along its slope. The slope of the hill is prop = 30^@ and the angle of the barrel to the horizontal beta = 60^@ . The initial velocity v of the shell is 21 m s^-1 . Then find the distance of point from the gun at which the shell will fall.

A cannot fires from under a shelter inclined at an angle alpha to the horizontal (Fig.). The cannot is at point A at a (distance l from the base of the shelter (point B). The initial velocity of the shell is v_(0) , and its trajectory lies in the plane of the figure. Determine the maximum range L_(max) of the shell.

A shot is fired with a velocity u at a very high vertical wall whose distance from the point of projection is x .The greatest height above the level of the point of projection at which the bullet can hit the wall is.

Two identical shells are fired from a point on the ground with same muzzle velocity at angle of elevation alpha=45^(@) and beta=tan^(-1)3 towards top of a cliff, 20 m away from the point of firing. If both the shells reach the top simultaneously, then height of the cliff is