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A ball is projected horizontally with a ...

A ball is projected horizontally with a speed v from the top of the plane inclined at an angle `45^(@)` with the horizontal. How far from the point of projection will the ball strikes the plane?

A

`(V^2)/g`

B

`sqrt2 V^2/g`

C

`(2v^2)/g`

D

`sqrt2[(2v^2)/g]`

Text Solution

Verified by Experts

The correct Answer is:
D

`a_(x)=g sin 45^(@), a_(y)=-g cos 45^(@)`
`S_(y)=0=v sin 45^(@)t-1/2 (g)/(sqrt2) t^(2) rArr t=(2v)/(g)`
`S_(x)=(v cos 45^(@))t+1/2 g/sqrt2 t^(2)=(2srt2)/(g) v^(2)`
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