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A particle is moving in a circle of radi...

A particle is moving in a circle of radius `r` centred at `O` with constant speed `v`. What is the change in velocity in moving from `A "to" B (/_ AOB = 40^@)` ?

A

` 2u sin 20^@`

B

`4u sin 40^@`

C

`2u sin 40^@`

D

`u sin 40^@`

Text Solution

Verified by Experts

The correct Answer is:
A
Change in velocity `=overset(-)(V)f-overset(-)V_(i)`
Its magnitude `|triangle overset(-)V|=sqrt(u^(2)+u^(2)-2u.u cos 40^(@)) |triangle overset(-)v|=2u sin 20^(@)`
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