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A particle starts travelling on a circle...

A particle starts travelling on a circle with constant tangential acceleration. The angle between velocity vector and acceleration vector, at the moment when particle completes half the circular track. Is

A

`tan ^(-1) (2pi)`

B

`tan^(-1) (pi)`

C

`tan^(-1) (3pi)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A
Let V : final velocity a: tangential acceleration `rArr V^(2)=2a_(t) (piR) rArr a_(r)=(V^(2))/(R)=2a_(t)pi`
Angle between velocity vector acceleration vector = Angle between tangential acceleration and total acceleration `=tan^(-1)""(a_(r))/(a_(t))=tan^(-1) (2pi)`
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