A projectile attains a certain maximum height H1 when projected from earth. If it is projected at the same angle and with the same initial speed from the moon, where the acceleration due to gravity is one-sixth that on earth, the maximum height attended by the projectile is `H_2`. THe ratio `H_2//H_1` is:

Explanation

To solve the problem, we need to find the ratio \( \frac{H_2}{H_1} \) where \( H_1 \) is the maximum height attained by a projectile on Earth and \( H_2 \) is the maximum height attained by the same projectile on the Moon.

### Step-by-Step Solution:

1. **Understanding the Maximum Height Formula**:
The maximum height \( H \) attained by a projectile launched with an initial velocity \( u \) at an angle \( \theta \) with respect to the horizontal is given by:
\[
H = \frac{u^2 \sin^2 \theta}{2g}
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