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A body of mass m thrown horizontally wit...

A body of mass m thrown horizontally with velocity v, from the top of tower of height h touches the level ground at a distance of 250m from the foot of the tower. A body of mass 2m thrown horizontally with velocity `v//2`, from the top of tower of height 4h will touch the level ground at a distance x from the foot of tower. The value of x is

A

250 m

B

500 m

C

125 m

D

`250sqrt(2)` m

Text Solution

Verified by Experts

The correct Answer is:
A
`t=sqrt((2h)/(g))`
Distance from the foot of twoer `d=vt=vsqrt((2h)/(g))=250m," when velocity "y=v/2" and the height of tower =4h"`
Then distance `x=v/2 sqrt((2(4h))/(g)) rArr x=v sqrt((2h)/(g))=250m`
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