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Match the entries of Column I and Column...

Match the entries of Column I and Column II.
COLUMN - I
(A) For a particle moving in a circle
(B) For a particle moving in a straight line
(C) For a particle undergoing projectile motion with the angle of projection `alpha:0 lt alpha lt pi/2`
(D) For a particle moving in space
COLUMN - II
(P) The acceleration may be perpendicular to its velocity.
(Q) The acceleration may be in the direction of velocity
(R) The acceleration may be at some angle `theta(0 lt theta lt pi/2)` with the velocity.
(S) The acceleration may be opposite to its velocity.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of matching the entries from Column I with those from Column II, we will analyze each entry in Column I and determine which statement from Column II corresponds to it. ### Step-by-Step Solution: **Step 1: Analyze Entry A (For a particle moving in a circle)** - In circular motion, the particle experiences centripetal acceleration directed towards the center of the circle, which is always perpendicular to the velocity of the particle (which is tangential to the circle). - Thus, the correct match for A is **P**: "The acceleration may be perpendicular to its velocity." **Step 2: Analyze Entry B (For a particle moving in a straight line)** - For a particle moving in a straight line, the acceleration can be in the same direction as the velocity (causing the speed to increase) or opposite to it (causing the speed to decrease). - Therefore, the correct matches for B are **Q**: "The acceleration may be in the direction of velocity" and **S**: "The acceleration may be opposite to its velocity." **Step 3: Analyze Entry C (For a particle undergoing projectile motion with angle of projection `alpha: 0 < alpha < pi/2`)** - In projectile motion, the acceleration due to gravity acts downward while the velocity has both horizontal and vertical components. At the highest point, the vertical component of velocity is zero, making the acceleration perpendicular to the horizontal velocity. - Therefore, the correct matches for C are **P**: "The acceleration may be perpendicular to its velocity" and **R**: "The acceleration may be at some angle `theta (0 < theta < pi/2)` with the velocity." **Step 4: Analyze Entry D (For a particle moving in space)** - A particle moving freely in space can have its acceleration in any direction relative to its velocity. It can be perpendicular, in the same direction, at an angle, or opposite to its velocity. - Therefore, all statements in Column II (P, Q, R, S) are valid for D. ### Final Matches: - A → P - B → Q, S - C → P, R - D → P, Q, R, S ### Summary of Matches: - **A** matches with **P** - **B** matches with **Q** and **S** - **C** matches with **P** and **R** - **D** matches with **P**, **Q**, **R**, and **S**

To solve the problem of matching the entries from Column I with those from Column II, we will analyze each entry in Column I and determine which statement from Column II corresponds to it. ### Step-by-Step Solution: **Step 1: Analyze Entry A (For a particle moving in a circle)** - In circular motion, the particle experiences centripetal acceleration directed towards the center of the circle, which is always perpendicular to the velocity of the particle (which is tangential to the circle). - Thus, the correct match for A is **P**: "The acceleration may be perpendicular to its velocity." ...
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