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The horizontal range of a projectile is ...

The horizontal range of a projectile is `4 sqrt(3)` times its maximum height. Its angle of projection will be

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6
`R=4sqrt3H rArr (2u_(x)u_(y))/(g) =4sqr3 (u_(y)^(2))/(2g) rArr u_(x)=sqrt3u_(y) rArr (u cos theta)/(u sin theta)=sqrt3 rArr theta=pi/6" radian"`.
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