Home
Class 12
PHYSICS
A projectile can have the same range R f...

A projectile can have the same range R for two angles of projection. If `t_(1)` and `t_(2)` be the times of flight in the two cases:-

A

`t _ 1 t _ 2 prop R ^ 2 `

B

` t _ 1 t _ 2 prop R `

C

`t _ 1 t _ 2 prop (1)/(R ) `

D

` t _ 1 t _ 2 prop (1)/(R^2 ) `

Text Solution

Verified by Experts

The correct Answer is:
B
For same range, angles of projection should be `theta and (90^(@)-theta)` So, time of flights. `t_(1)=(2u sin theta)/(g) and t_(2)=(2u sin (90^(@)-theta))/(g)=(2u cos theta)/(g)`
`t_(1)t_(2)=(4u^(2)sin theta cos theta)/(g^(2)) rArr t_(1)t_(2)=2/g ((u^(2) sin 2 theta))/(g)=(2R)/(g) rArr t_(1)t_(2) alpha R`
Promotional Banner

Similar Questions

Explore conceptually related problems

A projectille can have the same range R for two angles of projection. If t_(1) and t_(2) be the time of flight in the two cases, then find the relation between t_(1), t_(2) and R .

A projectile can have the same range 'R' for two angles of projection . If 'T_(1)' and 'T_(2)' to be times of flights in the two cases, then the product of the two times of flights is directly proportional to .

For a given velocity, a projectile has the same range R for two angles of rpojection if t_(1) and t_(2) are the times of flight in the two cases then

A projectile can have the same range R for two angle of projection . If t-1 and t_2 be the terms of flight in the two cased then the initial velocity of projectile is?

For a given velocity, a projectile has the same range R for two angles of projection. If t_(1) and t_(2) are the time of flight in the two cases, then t_(1) = t_(2) is equal to

A projectile can have same range R for two angles of projection. It t_1 and t_2 are the times of flight in the two cases, then what is the product of two times of flight ?

A projectile has the same range R for two angles of projections but same speed. If T_(1) and T_(2) be the times of flight in the two cases, then Here theta is the angle of projection corresponding to T_(1) .

A projectile has the same range R for angles of projections. If T_(1) and T_(2) be the times of fight in the two cases, then ( using theta as the angle of projection corresponding to T_(1) )

A projectile has same range for two angules of projection. If times of flight in two cases are t_(1) and t_(2) then the range of the projectilie is