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A force of 5N changes the velocity of a ...

A force of `5N` changes the velocity of a body from `10 ms^(-1)` to `20 ms^(-1)` in `5 sec`. How much force is required to bring about the same change in `2 sec`?

Text Solution

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`F_(1) = (dp)/(dt_(1)), F_(2) = (dp)/(dt_(2))` `:.` `F_(2) = F_(1) (dt_(1))/(dt_(2)), F_(2) = 5 xx (5)/(2) = 12.5 N`
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