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A block can slide on a smooth inclined p...

A block can slide on a smooth inclined plane of inclination `theta` kept on the floor of a lift. When the lift is descending with a retardation a , the acceleration of the block relative to the incline is

A

`sqrt((2L)/((g + a) sin theta))`

B

`sqrt((2L)/((g - a) sin theta))`

C

`sqrt((2L)/(a sin theta))`

D

`sqrt((2L)/(g sin theta))`

Text Solution

Verified by Experts

The correct Answer is:
A
Acceleration of block with respect to lift
`a_(r ) = (m (g + a) sin theta)/(m) (g + a) sin theta`
`s = (1)/(2) a_(r ) r^(2), t = sqrt((2s)/(a_(r))) = sqrt((2L)/((g + a) sin theta))`
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