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In the figure the wedge is pushed with a...

In the figure the wedge is pushed with an acceleration of `sqrt3 m//s ^(2)`. It is seen that the block start climbing up on the smooth inclined face of wedge . What will be the time taken by the block to reach the top?

A

`(2)/(sqrt(5)) s`

B

`(1)/(sqrt(5)) s`

C

`sqrt(5) s`

D

`(sqrt(5))/(2) s`

Text Solution

Verified by Experts

The correct Answer is:
B
FBD of m w.r.t wedge
Relative acceleration along the inclined plane
`a_(r ) = (m a cos theta - m g sin theta)/(m)`
`a cos theta - g sin theta`
`= (1.0 sqrt(3)) ((sqt(3))/(2)) - (10) ((1)/(2)) = 10 m//s^(2)`
`t = sqrt((2s)/(a_(r ))) = (sqrt(2 xx 1))/(10) = (1)/(sqrt(5)) s`
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