Home
Class 12
PHYSICS
All the surfaces are smooth as shown in ...

All the surfaces are smooth as shown in figure. The acceleration of mass m relative to wedge is :

A

g sin `theta`

B

g sin `theta` + a cos `theta`

C

g sin `theta` - a cos `theta`

D

a cos `theta`

Text Solution

Verified by Experts

The correct Answer is:
B
From free body diagram `N + m a sin theta = m g cos theta`

Acceleration of mass m relative to wedge `= ( mg sin theta + ma cos theta)/(m) = g sin theta + a cos theta`
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

In the situation shown below a block A of mass 5 kg is kept on the wedge B of mass 8 kg. All surfaces are smooth and string is massless, smooth and inextensible. Then acceleration of wedge B in m/ s^2 is?

A block of mass m is placed on the inclined sufrace of a wedge as shown in fig. Calculate the acceleration of the wedge and the block when the block is released. Assume all surfaces are frictionless.

Knowledge Check

  • All surfaces are smooth. The acceleration of mass m relative to the wedge is

    A
    `g sin theta`
    B
    `g sin theta+a cos theta`
    C
    `g sin theta-a cos theta`
    D
    `a cos theta`

  • In the arrangement shown in figure wedge of mass M moves towards left with an acceleration a. All surfaces are smooth. The acceleration of mass m relative to wedge is

    A
    `a//2`
    B
    `(2Ma)/(m)`
    C
    `(2(M+m)a)/(m)`
    D
    `((M+m)a)/(m)`

  • All surfaces are smooth The acceleration of mass m relative to the wedge is .

    A
    `g sin theta`
    B
    `g sin theta +a cos theta`
    C
    `g sin theta -a cos theta`
    D
    `a cos theta`

    • Similar Questions

    Explore conceptually related problems

    A rod of mass m is supported on a wedge of mass M shown in fig. Find the accelerations of rod a and wedge A in the arrangment. The friction between all contact surfaces in negligible.

    In the arrangement shown in figure-2.68 the masses of the wedge M and the body m are known. There is no friction at any of the surfaces. The mass of the pulleys and thread is negligible. Find the acceleration of the body m relative to the horizontal surface on which the wedge slides. [(sqrt(2)mg)/(M+2m)]

    System is shown in figure. All the surface are smooth. Rod is move by external agent with acceleration 9 m//s^(2) vertically downwards. Find the force exerted on the rod by the wedge.

    A block of mass m slides on the wooden wedge, which in turn slides backward on the horizontal surface. The acceleration of the block with respect to the wedge is : Given m = 8 kg, M = 16 mg Assume all the surfaces shown in the figure to be frictionless.

    A wedge (inclination theta = 30^(@) from horizontal) is moving with an acceleration a = 4 m//s^(2) vertically up as shown in figure. What is acceleration of block of mass 1 kg w.r.t & reaction by wedge on block respectively. All surface are smooth. Choose correct pair : (g = 10 m//s^(2))

    Home
    Profile