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In the figure shown, a particle of small...

In the figure shown, a particle of small mass m is joined to a very heavy mass M (M >> m) by a light string passing over a light pulley. The total downward force on the pulley by the string is :

A

mg

B

2 mg

C

4 mg

D

(M + m) g

Text Solution

Verified by Experts

The correct Answer is:
C
m moves upwards with acceleration `a = ((M -m)g)/((M + m)) = ((1 - (m)/(M))/(1 +(m)/(M)))g`,
`M gt gt m implies (m)/(M) = 0`
`:. A = g` T - mg = ma = mg `implies T = 2mg`
Downward force on pulley by string = 2T = 4 mg
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Knowledge Check

  • A particle of small m is joined to a very heavy body by a light string passing over a light pulley. Both bodies are free to move. The total downward force on the pulley is

    A
    `gt gtmg`
    B
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    C
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    D
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    A
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    B
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    C
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    D
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    B
    the tension in the string connecting masses is `((2Mm)/(M+m))g`
    C
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    D
    None of the above

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