Home
Class 12
PHYSICS
In the figure shown, a particle of small...

In the figure shown, a particle of small mass m is joined to a very heavy mass M (M >> m) by a light string passing over a light pulley. The total downward force on the pulley by the string is :

A

mg

B

2 mg

C

4 mg

D

(M + m) g

Text Solution

Verified by Experts

The correct Answer is:
C
m moves upwards with acceleration `a = ((M -m)g)/((M + m)) = ((1 - (m)/(M))/(1 +(m)/(M)))g`,
`M gt gt m implies (m)/(M) = 0`
`:. A = g` T - mg = ma = mg `implies T = 2mg`
Downward force on pulley by string = 2T = 4 mg
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle of small m is joined to a very heavy body by a light string passing over a light pulley. Both bodies are free to move. The total downward force on the pulley is

A light particle of mass m is connected to another very heavy particle by means of a light inextensible string that passes over a smooth pulley. The reading of the spring balance is approxinately

Two masses m and M(gt m) are joined by a light string passing over a smooth light pulley. The centre of mass of the system moves with an acceleration

Two identical masses are attached by a light string that passes over a small pulley, as shown . The table and the pulley are frictionless. The hanging block is moving

A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by

A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by