Home
Class 12
PHYSICS
A particle moves in the x-y plane under ...

A particle moves in the x-y plane under the action of a force `vecF` such that the value of its linear momentum `vecP` at any time t is `P_(x)=2` cost and `p_(y)=2sint`. What is the angle `theta` between `vecF` and P at a given time t?

Text Solution

Verified by Experts

The correct Answer is:
A
`vec(p) = 2 cos t hat(i) + 2 sin t hat(j)` `vec(F) = (vec(dp))/(dt) - 2 sin t hat(i) + 2 cos t hat(j)`
Hence `vec(p). Vec(F) = 0 implies vec(F)` is `_|_ r vec(p) implies theta = 90^(@)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle moves in the x-y plane under the action of a force vec(F) such that the value of its linear momentum vec(P) at any time is p_(x)=2cost,p_(y)=2sint. The angle theta between vec(F)and vec(P) at a given time t will be

A paarticle moves in the xy-plane under the action of a force F such that the componentes of its linear momentum p at any time t and p_(x)=2cos t, p_(y)=2sin t. the eangle between F and p at time l is

A particle moves in the x-y plane under the action of a force vec F such that its linear momentum vec P at any time t is vec P=2cost hati+2sint hatj . The angle between vec F and vec P at a given time t will be

A particle moves in the xy plane under the influence of a force such that its linear momentum is vecP(t) = A [haticos(kt)-hatjsin(kt)] , where A and k are constants. The angle between the force and momentum is

A particle moves in the X-Y plane under the influence of a force such that its linear momentum is oversetrarrp(t)=A[haticos(kt)-hatjsin(kt)] , where A and k are constants. The angle between the force and the momentum is

A particle moves in the x-y plane under is influence of a force such that its linear momentum is vec(P)(t)=A[hat(i)cos (kt)-hat(j)sin (kt)] , where A and k are constants Angle between the force and the momentum is:

A particle of mass m moves from A to C under the action of force vecF = 2xyhati + y^2 hatj , along different paths as shown in figure.

The momentum of a body is vec P =2 cos t hati +2 sin t hatj. What is the angle between the force vec F acting on the body and the momentum vec P ?