A rod `AB` of length `2m` is hinging at point A and its other end B is atteched to a platform on which a point of mass m is kept. Rod rotates about point `A` maintaing angle `theta = 30^(@)` with the vertical in such a way that platform remain horizontal and revolves on the horizontal circular path.If the coeffiicent of staic friction between the block and platform is `mu = 0.1` then find the maximum angular velocity in rad`s^(-1)` of rod so that the block does not slip on the plateform `(g = 10 ms^(-2))`

Answer

A

Explanation

`N = m g, mu N = m r omega^(2)`
`mu m g = m 2 sin theta omega^(2)` `implies omega = sqrt((mu g)/(2 sin theta)) = sqrt((0.1 xx 10)/(2 xx sin 30)) = 1 rad s^(-1)`