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A block of mass m placed on the inclined...

A block of mass m placed on the inclined surface of wedge of mass M. Block is clamped between two smooth vertical support such that it can move along vertical If all contact surface are smooth then acceleration of wedge is:

A

`A = g // sin theta`

B

`A = (mg sin theta. Cos theta)/(m sin^(2) theta + M cos^(2) theta)`

C

`A = (m g sin theta cos theta)/(m + M)`

D

`A = g sin theta`

Text Solution

Verified by Experts

The correct Answer is:
B

`mg - R cos theta = ma` …(i)
`R sin theta = MA` …..(ii)
`tan theta = (a)/(A) N = Mg + R cos theta` ….(iii)
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