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In the figure, at the free end of the li...


In the figure, at the free end of the light string, a force F is spplied to keep the suspended mass of 18 kg at rest. Then the force exerted by the cirling on the system (assume that the string segments are vertical and the pulleys are light and smooth) is:(`g=10(m)/(s^2)`)

Text Solution

Verified by Experts

The correct Answer is:
240
FBD of 18 kg. block
`implies T = 180 N`. (as it is at rest). For the lower pulley:
Clearly : `3T_(1) = T implies T_(1) = 60 N`
and for the upper pulley:
`T_(2) = 4T_(1) = 240 N`
where `T_(2)` is the force exerted by ceiling on the pulley.
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